Arithmetic & Numbers

Divisibility Rules Calculator

Enter a whole number. The calculator applies each divisibility rule — last digit, last two or three digits, digit sum — and tells you which divisors work and why.

Up to 18 digits
Try an example:
AnswerDivisible by 2, 3, 4, 6
  • Digit sum 12
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: yes  (last digit 6 is even)
    ÷ 3: yes  (digit sum 12)
    ÷ 4: yes  (last two digits 36)
    ÷ 5: no  (last digit 6)
    ÷ 6: yes  (must be divisible by both 2 and 3)
    ÷ 7: no  (remainder when divided by 7 is 4)
    ÷ 8: no  (last three digits 236)
    ÷ 9: no  (digit sum 12)
    ÷ 10: no  (last digit 6)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    1236 is divisible by 2, 3, 4, 6.

How to use the divisibility rules calculator

  1. Type a whole number.
  2. Read the list of divisors from 2 to 10.
  3. Open the steps to see the rule behind each yes or no.
  4. Use the rules to simplify fractions quickly.

The rules

2: last digit even
3: digit sum divisible by 3
4: last two digits divisible by 4
5: ends in 0 or 5
6: divisible by 2 and 3
7: remainder test
8: last three digits divisible by 8
9: digit sum divisible by 9
10: ends in 0

The rule for 7 is shown as the exact remainder check.

Worked examples

Each example below is generated by the same calculator you used above, so the working always matches the answer.

1236
AnswerDivisible by 2, 3, 4, 6
  • Digit sum 12
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: yes  (last digit 6 is even)
    ÷ 3: yes  (digit sum 12)
    ÷ 4: yes  (last two digits 36)
    ÷ 5: no  (last digit 6)
    ÷ 6: yes  (must be divisible by both 2 and 3)
    ÷ 7: no  (remainder when divided by 7 is 4)
    ÷ 8: no  (last three digits 236)
    ÷ 9: no  (digit sum 12)
    ÷ 10: no  (last digit 6)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    1236 is divisible by 2, 3, 4, 6.

360
AnswerDivisible by 2, 3, 4, 5, 6, 8, 9, 10
  • Digit sum 9
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: yes  (last digit 0 is even)
    ÷ 3: yes  (digit sum 9)
    ÷ 4: yes  (last two digits 60)
    ÷ 5: yes  (last digit 0)
    ÷ 6: yes  (must be divisible by both 2 and 3)
    ÷ 7: no  (remainder when divided by 7 is 3)
    ÷ 8: yes  (last three digits 360)
    ÷ 9: yes  (digit sum 9)
    ÷ 10: yes  (last digit 0)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    360 is divisible by 2, 3, 4, 5, 6, 8, 9, 10.

1001
AnswerDivisible by 7
  • Digit sum 2
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: no  (last digit 1 is odd)
    ÷ 3: no  (digit sum 2)
    ÷ 4: no  (last two digits 1)
    ÷ 5: no  (last digit 1)
    ÷ 6: no  (must be divisible by both 2 and 3)
    ÷ 7: yes  (remainder when divided by 7 is 0)
    ÷ 8: no  (last three digits 1)
    ÷ 9: no  (digit sum 2)
    ÷ 10: no  (last digit 1)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    1001 is divisible by 7.

98765
AnswerDivisible by 5
  • Digit sum 35
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: no  (last digit 5 is odd)
    ÷ 3: no  (digit sum 35)
    ÷ 4: no  (last two digits 65)
    ÷ 5: yes  (last digit 5)
    ÷ 6: no  (must be divisible by both 2 and 3)
    ÷ 7: no  (remainder when divided by 7 is 2)
    ÷ 8: no  (last three digits 765)
    ÷ 9: no  (digit sum 35)
    ÷ 10: no  (last digit 5)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    98765 is divisible by 5.

Common mistakes to avoid

Checking 6 with only one rule

A number needs both the 2-rule and the 3-rule to be divisible by 6.

Using the digit sum for 4

Divisibility by 4 depends on the last two digits, not the digit sum.

Misapplying the digit-sum rule for 9

The digit sum must itself be a multiple of 9, not just of 3.

Frequently asked questions

Why does the digit-sum rule work?

Because 10 leaves remainder 1 when divided by 3 or 9, so every power of ten does too, and a number has the same remainder as its digit sum.