Arithmetic & Numbers · Grades 4–8

Divisibility Rules for 2 to 10, Explained

Divisibility Rules for 2 to 10, Explained — illustration
Short answer: Look at the last digit for 2, 5 and 10, the last two or three digits for 4 and 8, and the digit sum for 3 and 9. Applying the rules to 1,236 gives: Divisible by 2, 3, 4, 6.

Rules by last digits

  • 2: the last digit is even
  • 5: the last digit is 0 or 5
  • 10: the last digit is 0
  • 4: the last two digits are divisible by 4
  • 8: the last three digits are divisible by 8

Rules by digit sum

A number is divisible by 3 when its digits add to a multiple of 3, and by 9 when they add to a multiple of 9. This works because every power of ten leaves a remainder of 1 when divided by 3 or 9.

1,236
AnswerDivisible by 2, 3, 4, 6
  • Digit sum 12
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: yes  (last digit 6 is even)
    ÷ 3: yes  (digit sum 12)
    ÷ 4: yes  (last two digits 36)
    ÷ 5: no  (last digit 6)
    ÷ 6: yes  (must be divisible by both 2 and 3)
    ÷ 7: no  (remainder when divided by 7 is 4)
    ÷ 8: no  (last three digits 236)
    ÷ 9: no  (digit sum 12)
    ÷ 10: no  (last digit 6)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    1236 is divisible by 2, 3, 4, 6.

Combining rules

A number is divisible by 6 if it passes both the 2-rule and the 3-rule. For 360 the result is Divisible by 2, 3, 4, 5, 6, 8, 9, 10.

360
AnswerDivisible by 2, 3, 4, 5, 6, 8, 9, 10
  • Digit sum 9
Step-by-step working 2 steps
  1. 1
    Apply each divisibility rule
    ÷ 2: yes  (last digit 0 is even)
    ÷ 3: yes  (digit sum 9)
    ÷ 4: yes  (last two digits 60)
    ÷ 5: yes  (last digit 0)
    ÷ 6: yes  (must be divisible by both 2 and 3)
    ÷ 7: no  (remainder when divided by 7 is 3)
    ÷ 8: yes  (last three digits 360)
    ÷ 9: yes  (digit sum 9)
    ÷ 10: yes  (last digit 0)

    Rules: 2, 5, 10 look at the last digit; 4 and 8 at the last two or three digits; 3 and 9 at the digit sum; 6 needs 2 and 3.

  2. 2
    Result

    360 is divisible by 2, 3, 4, 5, 6, 8, 9, 10.

The awkward one: 7

There is a quick trick for 7, but the remainder test is more reliable. For 1001 the only divisor from 2 to 10 is: Divisible by 7.

Common mistakes

Using the digit sum for 4 or 8

These depend on the last two or three digits, not the sum.

Forgetting both conditions for 6

Divisible by 2 and by 3 are both required.

Mis-adding digits

Re-add the digit sum if it is still large.

Put it into practice. Try your own numbers in the Divisibility Rules Calculator and compare each step with the method above.

Frequently asked questions

Is there a rule for 11?

Yes: the alternating sum of the digits must be a multiple of 11.

Written and reviewed by Mateuss M.

Mateuss M. writes and reviews mathematical content for CalcSolver, focusing on online calculators, formulas, equations, and practical math tools. He reviews calculator functionality, calculation methods, formulas, examples, and explanations to help ensure that each tool is clear, useful, and easy to understand.

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